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With this distance and time value, I can simply plug it into the kinematic equation and solve for the acceleration. This would give an acceleration of 0.1053 m/s 2.
Key fact The gradient of speed-time and velocity-time graphs represent acceleration. The area under a speed-time graph represents the distance travelled.
A negative gradient shows the rate of “slowing down” or deceleration. Velocity-time graphs show velocity on the vertical axis. Acceleration is still represented by the gradient. Key fact The ...
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