Mar 13, 2011 · The best two options are BufferedReader and Scanner.. The most widely used method is Scanner and I personally prefer it because of its simplicity and easy implementation, …

Mar 22, 2012 · If you use the nextLine() method immediately following the nextInt() method, nextInt() reads integer tokens; because of this, the last newline character for that line of integer …

Apr 30, 2015 · nextLine() reads everything up to and including the next newline character. However, nextInt() only reads the characters that make up the integer, and if the integer is the …

Jul 9, 2013 · In java we can read input values in 6 ways: Scanner Class; BufferedReader; Console class; Command line; AWT, String, GUI; System properties; Scanner class: present in …

Mar 29, 2014 · I am a newbie to Java, and I'm trying to get a string from an input with multiple lines. e.g. a string ="The quick brown fox jumps over the lazy dog. The quick brown fox jumps …

Sep 15, 2016 · One can use the delimiter function to segregate your input as shown below. import java.util.Scanner ...

Since you know that you want to have an array of 20 string: String[] array = new String[20]; Then your for loop should use the length of the array to determine when the loop should stop. Also …

May 2, 2010 · The question is "How to read from standard input". A console is a device typically associated to the keyboard and display from which a program is launched. You may wish to …

Jan 1, 2014 · Use new java.io.IO class previewed in Java 24. String input = IO.readln ( "Enter text: " ); Caveat: This Answer is based on a preview feature which may change or be …

For completeness here is Java 9 solution: public static String toString(InputStream input) throws IOException { return new String(input.readAllBytes(), StandardCharsets.UTF_8); } This uses …