Apr 27, 2016 · You've set the for loop to run as long as x is less than 3, but you've declared x to be equal to 3. Therefore, the condition x<3 is never met, so the loop is never run. Here's what …

Oct 27, 2012 · Scanner s2 = new Scanner(System.in); for(int i=0; i < this.num_choices; i++) { if(s2.hasNext()) { System.out.println("Enter choice " + (i+1) +":"); String ch = s2.next(); …

Feb 6, 2013 · Use nextLine() instead of next() when scanning the opponent team name. Replace: sAwayTeam = scanInput.next(); with sAwayTeam = scanInput.nextLine(); The reason it loops …

Apr 17, 2025 · We can use the Scanner class with loops to take input for individual array elements (to use this technique, we must know the length of the array). In this example, we will …

Mar 18, 2021 · Learn how to use Java's Scanner to get user input, iterate over an input String, and continue prompting for input until the user is done....more.

The Scanner class is used to get user input, and it is found in the java.util package. To use the Scanner class, create an object of the class and use any of the available methods found in the …

Apr 22, 2025 · Follow these steps to take user input using Scanner class: Import the Scanner class using import java.util.Scanner; Create the Scanner object and connect Scanner with …

Jan 8, 2024 · In this article, we’ve explored how to write a Java method to read user input until a condition is met. The two key techniques are: Using the Scanner class from the standard Java …

Jul 13, 2023 · Now that we know how to use loops, let’s discuss a common structure for reading and parsing user input from the terminal using a loop. In many of our prior projects, we’ve …

Sep 28, 2013 · for (int i = 0; i < n; i++) { // Begin For Loop. if (i == 0) { System.out.println("Enter First Number: "); while (!input.hasNextDouble()) { System.out.println("Please enter a number …