Oct 5, 2008 · Calculating the number of divisor of a given number doesn't need to calculate all the divisors. It's a different problem, if you think it's not then look for "Divisor function" on …

I want to find all divisors of a number in Python. I'm doing this greatly in Javascript, C#, Java, but my Python code work only with print statement correctly. But I don't want to print divisors, I …

Jan 8, 2022 · Given a number n, I want to generate a sorted list of all the unique divisors of n (with no duplications). Solving this problem is really straight forward, but what I'm interested in is the …

Jan 21, 2019 · # I took the s off of "divisors" since it's actually a single number integer % divisor == 0 Think of it this way, if integer is 50, and divisor is 2, with the way you had it, it would be: 2 …

Sep 14, 2012 · You can find all the divisors of a number by calculating the prime factorization. Each divisor has to be a combination of the primes in the factorization. If you have a list of …

Jan 16, 2024 · @wim I'm doing a for i in range(2, 100000): find_divisors(j) and the same with find_divisors_v2 and the first one takes 2.1s and the second one takes 1.1s (rough average). If …

To be clear, you're trying to find all divisors of a number, not all multiples.There are an infinite number number of multiples for every num aside from 0, so "finding them all" is nonsensical; …

Jul 23, 2011 · This solution works in both Python 2 and Python 3 with no imports and is much more readable. I haven't tested the performance of this approach, but asymptotically it should …

@Mathai because we divide the divisors out of the number, we can stop when i*i > n. Then the last n is the biggest factor of the original number (if we replace the inner while with an if : if …

Nov 25, 2016 · Start by defining a get_divisors function: def get_divisors(num): return [i for i in range(1, num) if num % i == 0] Then your sum_divisors function is simply: def …