Mar 13, 2011 · The best two options are BufferedReader and Scanner.. The most widely used method is Scanner and I personally prefer it because of its simplicity and easy implementation, …

Nov 25, 2014 · I am writing a program that asks the user to input his name, address and phone number. When the data is entered the program shall print the data and ask the user to verify …

comparing a string to an input form user. java. 1. Validating User input strings. 0. Java check String input.

Nov 7, 2014 · Having imported java.util.Scanner, to get input from the user as a String, create a Scanner object that parameterizes System.in and assign userChoice the value of nextLine() …

Mar 22, 2012 · The problem I'm having is that the Scanner.next() method only returns the first word before a space. So if the input is "My Birthday", the description of that instance of an …

Since you know that you want to have an array of 20 string: String[] array = new String[20]; Then your for loop should use the length of the array to determine when the loop should stop. Also …

Mar 31, 2015 · Instead of input.nextInt() you can just put input.next() and that will get the next immediate string value entered. You can also do input.nextLine() if I remember right and that …

Dec 28, 2014 · create array list entry String equals "" do this loop get input from user put it into entry String add entry String into array list while entry String doesn't equal "quit" for each item …

Well, let's look at it with the word 'HELLO' as input. You can tell, that the length of the string is 5, and the first letter (H) has the index 0, the second letter 1, ... and the last one has the index 4, …

Feb 4, 2017 · Final outcome should print out as follows: Enter input string: Jill, Allen First word: Jill Second word: Allen Enter input string: Golden , Monkey First word: Golden Second word: …