I want to find all divisors of a number in Python. I'm doing this greatly in Javascript, C#, Java, but my Python code work only with print statement correctly. But I don't want to print divisors, I …

Aug 21, 2024 · Given a Python file, we need to call a function in it defined in any other Python file. Example: Suppose there is a file test.py which contains the definition of the function …

Dec 7, 2013 · This first snippet defines a Python function that returns a list of the prime numbers up to a given integer. It uses the Sieve of Atkin, which is a modern algorithm that optimizes the …

May 28, 2022 · In many situations, we will need to call a function that is used in many other files of a project and is lying in some common functionality file. In this tutorial, we covered the different …

Jul 29, 2019 · Using unique prime factorisations and itertools to find all the divisors of a number.

This function takes in a number and returns all divisors for that number. list_to_number() is a function used to retrieve a list of prime numbers up to a limit, but I am not concerned over the …

Oct 5, 2008 · Given your factorGenerator function, here is a divisorGen that should work: factors = list(factorGenerator(n)) nfactors = len(factors) f = [0] * nfactors. while True: yield …

Mar 7, 2016 · from math import sqrt; from itertools import count, islice def is_prime(n): return n > 1 and all(n%i for i in islice(count(2), int(sqrt(n)-1))) def prime_divisors(n): prime_list = [] …

Jan 21, 2019 · def divisor_generator (): integer = input ("Enter a number:") integer = int (integer) list = [] for divisors in range (1, integer+1): if integer%divisors == 0: list.append (divisors) print …

Mar 7, 2016 · def prime_divisors(n): ns = 2 divisors = [] while n > 1: if n % ns == 0: divisors.append(ns) while n % ns == 0: # add this loop, to avoid duplicated factors n = (n / ns) …