Nov 27, 2017 · Hi, I'm relatively new to Matlab. This is my code: b = 0:3; for q = 0:10:20 XY = (40 + 2*q) + cosd(b) end And the output on the command window would be: XY = 41.000...

Dec 23, 2015 · You need to create a new matrix, and use two indices so that Matlab knows it is assigning to a column in a 2D matrix. NewMatrix = zeros(21, length(element)); for i = …

Dec 27, 2023 · Following these tips will allow you to harness the algorithmic power of for loops for complete matrix creation flexibility within your MATLAB code. The ability to fully customize …

Jul 6, 2012 · I am pretty new to matlab and I am trying create a matrix from a column vector. The problem: (This is a simplified version of my 100 x 1 vector and 100 x100 matrix.) The column …

Jan 13, 2025 · What I need to do is take the matrix (A) and after each loop update A to create one matrix. For instance, in the image below A is produced on the first loop, during loop 2 A …

May 12, 2014 · The idea is to generate a entire matrix (or structure, I suppose both are the same...) using a for loop (or may be there is a way to do it without any case of loop...). Does …

Feb 6, 2022 · I want to write a for loop that will create matrix of w=10x5 (10rows, 5 columns) where by column 1 will be the first 10 elements of X (1 to 10), column 2 (11 to 20) and so on …

Apr 27, 2018 · I need to create a matrix that increases or decreases in size with the change in variable n. The matrix should be having only one column and the number of rows need to …

Jul 2, 2014 · Easy, do not use for loops: I = I0*(w0/w)^2*exp(-2*(M(:,:,1).^2 + M(:,:,2).^2)/w^2); mask = abs(M(:,:,1)) < d/2 & abs(M(:,:,2)) < d/2; I(~mask) = 0; Done! Otherwise, I(i,j) will make …

Mar 17, 2022 · I'm looking to use this for-loop, where the condition statement of the loop defines a value for the variable, P, in the B matrix to solve F in the equation AF = B to get multiple output …